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If the coefficient of performance of a refrigerator is 5 and operates at the room temperature (27^@C), find the temperature inside the refrigerator. |
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Answer» SOLUTION :Coefficient of performance, `beta=5` `T_1`=27+273=300 K `T_2`=? Coefficient of performance , `beta=T_2/(T_1-T_2)` `THEREFORE 5=T_2/(300-T_2)` `therefore 1500-5T_2=T_2` `therefore 1500=6T_2` `therefore T_2=1500/6`=250 K `therefore t_2`=250-273 =`-23^@`C |
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