1.

If the collision frequency of a gas at 1 atm pressure is Z, then its collision frequency at 0.5 atm is

Answer»

0.25 Z
0.50 Z
Z
2Z

Solution :At CONSTANT `T,Z PROP P^(2)`
`:. (Z_(1))/(Z_(2))=(P_(1)^(2))/(P_(2)^(2)), i.e., (Z)/(Z_(2))=((1)^(2))/((0.5)^(2))" or " Z_(2)=0.25" Z"`


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