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If the collision frequency of a gas at 1 atm pressure is Z, then its collision frequency at 0.5 atm is |
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Answer» 0.25 Z `:. (Z_(1))/(Z_(2))=(P_(1)^(2))/(P_(2)^(2)), i.e., (Z)/(Z_(2))=((1)^(2))/((0.5)^(2))" or " Z_(2)=0.25" Z"` |
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