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If the components of air areN_(2), 78%, O_(2), 21%, Ar, 0-9% and CO_(2), 0-1%by volume, what would be the molecular weight of air? |
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Answer» Solution :The volume RATIO of the gases will be the same as their mole ratio (Avogadro.s principle) `THEREFORE` mol. Wt of air `=(78 xx 28 + 21 xx 32 + 0.9 xx 40 + 0.1 xx 44)/(78 + 21 + 0.9 + 0.1)` (`N_(2) = 28, O_(2) = 32, Ar = 40` and `CO_(2) = 44`) |
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