If the concentration of glucose (C_(6)H_(12)O_(6)) in blood is0.9 g L^(-1) what will be the molarity of glucose in blood ?

If the concentration of glucose (C_(6)H_(12)O_(6)) in blood is0.9 g L^

1.	If the concentration of glucose (C_(6)H_(12)O_(6)) in blood is0.9 g L^(-1) what will be the molarity of glucose in blood ?
Answer» 5 M 50 M 0.005 M 0.5 M Solution :`0.9 G L^(-1)` means that 1000 mL (or 1 L) solutioncontains 0.9 g of glucose. `:.` Number of moles `= 0.9g` glucose `= (0.9)/(180)` mol glucose `= 5 xx 10^(-3)` mol glucose (molecular mass of glucose `(C_(6)H_(12)O_(6)) = 12 xx 6 + 12 xx 1 + 6 xx 16=180 U`) i.e., 1 L solution contains 0.05 mole glucose or the molarity of glucose is 0.005 M.