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If the concentration of glucose `(C_(6)H_(12)O_(6))` in blood is 0.9 g `L^(-1)`, what will be the molarity of glucose in blood?A. 5MB. 50MC. 0.005MD. 0.5M |
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Answer» In the given question 0.9 `gL^(-1)` means that 1000(mL) solution contains 0.9g of glucose. `therefore` Number of moles `=0.9g "glucose"=(0.9)/(180)` mol glucose `=5xx10^(-3)` mol glucose (where , molecular mass of glucose `(C_(6)H_(12)O_(6))=12xx6+12xx1+6xx16=180u`) i.e. L solution contains 0.05 mole glucose or the molarity of glucose is 0.005M. |
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