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If the coordinate axes are the bisectors of the angles between the pair of lines `ax^(2)+2hxy+by^(2)=0`, thenA. `a+b=0`B. `h=0`C. `h ne 0, a+b=0`D. `a+b ne 0` |
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Answer» Correct Answer - B The combined equation of the angle bisectors of lines given by `ax^(2)+2hxy+by^(2)=0`, is `(x^(2)-y^(2))/(a-b)=(xy)/(h)` `rArr" "(a-b)xy=(x^(2)-y^(2))h" …(i)"` It is given that the coordinate axes are the bisectors of the angles between the lines given by `ax^(2)+2hxy+by^(2)=0`. So, their combined equation is `xy=0" ...(ii)"` From (i) and (ii), we get `h=0, a-b ne0` |
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