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The angle between the lines `2x^2-7x y+3y^2=0`is`60^0`2. `45^0`3. `tan^(-1)(7//6)`4. `30^0`A. `60^(@)`B. `45^(@)`C. `tan^(-1)((7)/(6))`D. `30^(@)` |
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Answer» Correct Answer - B Here, `=2, b=3 and h=-(7)/(2)` Let `theta` be the angle between the lines represented by `2x^(2)-7xy+3y^(2)=0`. Then, `tan theta=(2sqrt((49)/(4)-6))/(5)=1rArrtheta=45^(@)` |
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