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If the current sensitivity of a galvanometer is doubled, then its voltage sensitivity will beA. doubledB. halvedC. unchangedD. four times |
Answer» Correct Answer - C Current sensitivity of galvanometer is deflection per unit current i.e. `(phi)/(I)=(NAB)/(k)" …(i)"` Similarly voltage sensitivity is deflection per unit voltage i.e. `(phi)/(V)=((NAB)/(k))(I)/(V)=((NAB)/(k))=(1)/(R)" ...(ii)"` From (i) and (ii) Voltage sensitivity `="current sensitivity"xx(1)/("resistance")` Now if current sensitivity is doubled, then the resistance in the circuit will also be doubled since it is proportional to the length of the wire, then voltge sensitivity `=(2xx"current sensitivity")xx(1)/((2xx"resistance"))` `="(current sensitivity)"xx(1)/("(resistance)")` Hence, voltage sensitivity will remain unchanged. |
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