If the de Broglie wavelength of a particle of mass m is 100 times its velocity, then its value in terms of its mass (m) and Planck's constant (h) is

If the de Broglie wavelength of a particle of mass m is 100 times its

1.	If the de Broglie wavelength of a particle of mass m is 100 times its velocity, then its value in terms of its mass (m) and Planck's constant (h) is
Answer» `(1)/(10) sqrt((m)/(h))` `10 sqrt((h)/(m))` `(1)/(10) sqrt((h)/(m))` `10 sqrt((m)/(h))` Solution :Suppose velocity `(V) = X` Then DE Broglie wavelength `(LAMDA) = 100x` Now, `lamda =(h)/(mv) " " :.100x = (h)/(MX)` or `x^(2) = (1)/(100) (h)/(m) or x = (1)/(10) sqrt((h)/(m))` Hence, `lamda = 100x = 10 sqrt((h)/(m))`