If the density of a sphere is reduced to `1//8` of its original value, then the radius of the sphere is `"_________"` times its original radius (assume that there is no change in mass). SA. 2B. 4C. `1//2`D. `1//4`

If the density of a sphere is reduced to `1//8` of its original value,

1.	If the density of a sphere is reduced to `1//8` of its original value, then the radius of the sphere is `"_________"` times its original radius (assume that there is no change in mass). SA. 2B. 4C. `1//2`D. `1//4`
Answer» Correct Answer - A Density = `"mass"/"volume"` When the density is decreased to `1/8`th of its original value, then volume increases by times the original value. `v=4/3pir^(3)` `v_(1)=8 " v "` `4/3pir_(1)^(3)=8 xx4/3pi r^(3)` `r_(1)=8 r^(3)` ` r_(1)=2 " 0 "`

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If the density of a sphere is reduced to `1//8` of its original value, then the radius of the sphere is `"_________"` times its original radius (assume that there is no change in mass). SA. 2B. 4C. `1//2`D. `1//4`

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