If the density of metanol is 0.793 kg/l. calculate its molarity

1.	If the density of metanol is 0.793 kg/l. calculate its molarity
Answer» Answer: *MASS of methanol required is* *M=Volume of SOLUTION × Molariy of solution×Molar mass of methanol* *M=Volume of solution × Molariy of solution×Molar mass of methanol=2.5×0.25×32=20 g.* *M=Volume of solution × Molariy of solution×Molar mass of methanol=2.5×0.25×32=20 g.Volume of methanol NEEDED = mass/density* *M=Volume of solution × Molariy of solution×Molar mass of methanol=2.5×0.25×32=20 g.Volume of methanol needed = mass/density=20/0.793* *M=Volume of solution × Molariy of solution×Molar mass of methanol=2.5×0.25×32=20 g.Volume of methanol needed = mass/density=20/0.793=25.22 ML.*

Answer»

Answer:

MASS of methanol required is

M=Volume of SOLUTION × Molariy of solution×Molar mass of methanol

M=Volume of solution × Molariy of solution×Molar mass of methanol=2.5×0.25×32=20 g.

M=Volume of solution × Molariy of solution×Molar mass of methanol=2.5×0.25×32=20 g.Volume of methanol NEEDED = mass/density

M=Volume of solution × Molariy of solution×Molar mass of methanol=2.5×0.25×32=20 g.Volume of methanol needed = mass/density=20/0.793

M=Volume of solution × Molariy of solution×Molar mass of methanol=2.5×0.25×32=20 g.Volume of methanol needed = mass/density=20/0.793=25.22 ML.

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