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If the density of some lake water is `1.25 g mL^(-1)` and contains `92g` of `Na^(o+)` ions per `kg` of water, calculate the molality of `Na^(o+)` ions in the lake. |
Answer» Molar mass of `Na=23 " g mol"^(-1)` `therefore ` No. of moles of `Na^(+)` ions present `=(92)/(23)=4 ` moles `therefore "Molality"=(4xx1000)/(1000)=4 m` |
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