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If the density of water is 1 g `cm^(-3)` then the volume occupied by one molecule of water is approximatelyA. `3xx10^(-23)mL`B. `6xx10^(-22)mL`C. `3xx10^(-21)mL`D. `9xx10^(-23)mL` |
Answer» Correct Answer - 1 `1xx10^(3)kg//m^(3)=1g//mL=1gm//c c" " [` Since ,`1m^(3)=10^(6)cm^(3)=10^(6)mL]` `6.022xx10^(23)H_(2)O` molecule weight `rarr 18g` `1H_(2)O` molecule weight `rarr (18)/(6.022xx10^(23))g=3xx10^(-23)g` `d=(mass)/(volume)," "` So, volume`=(3xx10^(-23))/(1(g//mL))=3xx10^(-23)mL` |
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