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If the density of water is 1 g `cm^(-3)` then the volume occupied by one molecule of water is approximatelyA. `18 cm^(3)`B. `22400 cm^(3)`C. `6*02xx10^(-23) cm^(3)`D. `3*0xx10^(-23) cm^(3)` |
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Answer» Correct Answer - C Mass of 1 molecule of water `=("GMM")/(N_(0))=(18)/(6*02xx10^(23))g` `:.` Volume of 1 molecule of water `= ("Mass")/("Density")` `=(18xx10^(-23))/(6*02xx1)=3*0xx10^(-23) mL`. |
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