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If the density of water is 1 g `cm^(-3)` then the volume occupied by one molecule of water is approximatelyA. (a)`6.023xx10^(-3) cm^(3)`B. (b)`3.0xx10^(-3) cm^(3)`C. (c )`5.5xx10^(-23) cm^(3)`D. (d)`9.0xx10^(-23) cm^(3)` |
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Answer» Correct Answer - b `1000 g H_(2)O=1000 cm^(3) H_(2)O` `1000/18 "mole" H_(2)O=1000 cm^(3) H_(2)O` `1000/18xx6.023xx10^(23)` molecule of `H_(2)O` `=1000 cm^(3) H_(2)O` `implies ` Volume of `1 "molecule"=1000/1000xx18/(6.023xx10^(23))` `=3.0xx10^(-23) cm^(3)`. |
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