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If the derivative of (ax – 5)e3x at x = 0 is -13, then the value of a is … (a) 8 (b) -2 (c) 5 (d) 2 |
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Answer» (d) 2 y = (ax – 5)e3x dy/dx = y’ = (ax – 5) (3e3x) + e3x (a) = e3x[3ax – 15 + a] Given dy/dx = -13 at x = 0 ⇒ [-15 + a] = -13 ⇒ a = -13 + 15 a = 2 |
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