1.

If the derivative of (ax – 5)e3x at x = 0 is -13, then the value of a is … (a) 8 (b) -2 (c) 5 (d) 2

Answer»

(d) 2

y = (ax – 5)e3x 

dy/dx = y’ = (ax – 5) (3e3x) + e3x (a) 

= e3x[3ax – 15 + a] 

Given dy/dx = -13 at x = 0 

⇒ [-15 + a] = -13 

⇒ a = -13 + 15 

a = 2



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