If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across the length of scale of length 20 cm long.

If the diameter of a carbon atom is 0.15 nm, calculate the number of c

1.	If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across the length of scale of length 20 cm long.
Answer» Solution :Diameter of CARBON atom `= 0.15 NM = 0.15 xx 10^(-9) m = 1.5 xx 10^(-10)m` Length along which ATOMS are to be placed `= 20 cm = 20 xx 10^(-2) m = 2 xx 10^(-1)m` `:.` No. of C-atoms which can be placed along the line `= (2 xx 10^(-1))/(1.5 xx 10^(-10)) = 1.33 xx 10^(9)`