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If the diameter of a carbon atom is `0.15 nm`, calculate the number of carbon atom which can be placed side by side in a straight line length of scale of length `20 cm` long. |
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Answer» Diameter of carbon atom `=0.15 nm` `=0.15xx10^(-9) m=1.5xx10^(-10) m` Length along which atoms are to be placed `=20 cm` `=20xx10^(-2) m=2xx10^(-1)m` :. Number of C atoms which can be placed along the length `=(2xx10^(-1))/(1.5xx10^(-10))=1.33xx10^(9)` |
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