If the diameter of a carbon atom is 0.15 nm, calculate the number of c

1.	If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.
Answer» Length of the scale = 20 cm = 20 x 10⁷ nm = 2 x 10⁸ nm Diameter of the carbon atom = 0.15 nm Number of carbon atoms which can be placed side by side across the scale = {(2 x 10⁸ nm)}/{0.15 nm} = 1.33 x 10⁹

If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.

Answer»

Length of the scale = 20 cm = 20 x 10⁷ nm = 2 x 10⁸ nm

Diameter of the carbon atom = 0.15 nm

Number of carbon atoms which can be placed side by side across the scale = {(2 x 10⁸ nm)}/{0.15 nm} = 1.33 x 10⁹