1.

If the difference of the roots of x2 - px + q = 0 is unity, thenA.  p2 + 4q = 1B. p2 - 4q = 1C. p2 + 4q2 = (1 + 2q)2D. 4p2 + q2 = (1 + 2p)2

Answer»

Difference of the roots = \(\frac{\sqrt{D}}{|a|}\)

1 = \(\frac{\sqrt{b^2-4ac}}{|a|}\) 

1 =\(\frac{\sqrt{(-p)^2}-4(1)(q)}{|1|}\)

1 = p2 – 4q = 1 

p2 – 4q + 4q2 – 4q2 = 1 

p2 + 4q2 = 1 + 2(2)(q) + (2q)2 

p2 + 4q2 = (1 + 2q)2


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