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If the dimension of a physical quantity are given by `M^a L^b T^c,` then the physical quantity will beA. pressure if `a = b, b =- 1, c =- 2`B. velocity is `a = 1,b = 0, c =- 1`C. acceleration if `a = 1, b =1, c =- 2`D. force if `a = 0, b =- 1, c =-2` |
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Answer» Correct Answer - A (i) Dimensions of velocity `= [M^(0)L^(1)T^(-1)]` Here, `a = 0, b = 1, c =- 1` (ii) Dimensions of acceleration `[M^(0)L^(1)T^(-2)]` Here, `a = 0, b = 1, c =- 2` (iii) Dimensions of force `= [M^(1)L^(1)T^(-2)]` Here, `a = 1,b = 1,T =- 2` (iv) Dimensions of pressure `=[ML^(1)L^(-2)T^(-2)]` `:.` Here, `a = 1, b =- 1,c =- 2` `:.` The physical quantity is pressure. |
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