1.

If the dimensions of a physical quantity are given by M^(a)L^(b) T^(c), then the physical quantity will be

Answer»

velocity if a 1, B = 0, C =-1
acceleration if a = 1, b=1, c = -2
FORCE if a = 0, b = - 1, c = - 2
pressure if a = 1, b =-1, c = -2

Solution :Pressure, `P= ("force")/("area")= ("MASS" xx "acceleration")/("area")`
`:. [P]= ([M^(1)LT^(-2)])/([L^(2)])= [M^(1)L^(-1)T^(-2)]= M^(a)L^(b)T^(c)`
`:.`a=1, b =-1, c=-2


Discussion

No Comment Found