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If the dimensions of a physical quantity are given by M^(a)L^(b) T^(c), then the physical quantity will be |
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Answer» velocity if a 1, B = 0, C =-1 `:. [P]= ([M^(1)LT^(-2)])/([L^(2)])= [M^(1)L^(-1)T^(-2)]= M^(a)L^(b)T^(c)` `:.`a=1, b =-1, c=-2 |
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