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If the displacement of a particle is `(2t^(2) +t +5)` meter then, what will be acceleration at `t = 5sec.` |
Answer» `v = (dx)/(dt) = (d)/(dt) (2t^(2)+t+5) = 4t +1m//s` and `a = (dv)/(dt) = (d)/(dt) (4t+1) a = 4m//s^(2)` |
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