If the displacement of simple pendulum at any time is 0.02 m and acceleration is 2m//s^(2), then in this time angular velocity will be

If the displacement of simple pendulum at any time is 0.02 m and accel

1.	If the displacement of simple pendulum at any time is 0.02 m and acceleration is 2m//s^(2), then in this time angular velocity will be
Answer» 100 rad/s 10 rad/s 1 rad/s `0.1` rad/s Solution :ACCELERATION `\|ALPHA\|=omega^(2)x` or `omega=sqrt(alpha)/(x)` `=sqrt((2)/(0.002))=10rad//s`