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If the distance between incenter and one of the excenter of anequilateral triangle is 4 units, then find the inradius of the triangle. |
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Answer» Distance between excenter `I_(1) and` incenter I is `II_(1) = 4R sin.(A)/(2) = 4` (given) Since triangle, we have `4 = 4R sin.(pi)/(6)` or `R = 2` `:. R = 2r = 2` or `r = 1` |
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