If the distance between the first maxima and fifth minima of a double-slit pattern is 7 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength of the light used isA. 600 nmB. 525 nmC. 467 nmD. 420 nm

If the distance between the first maxima and fifth minima of a double-

1.	If the distance between the first maxima and fifth minima of a double-slit pattern is 7 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength of the light used isA. 600 nmB. 525 nmC. 467 nmD. 420 nm
Answer» Correct Answer - A For minima `y_(n)=(2n-1)(lamdaD)/(2d)` where n is the no. of minimum For maxima `y_(n)=(nlamdaD)/(d)` `y_(5^(th)"dard")=(9lamdaD)/(2d):y_(1^(@)" maxima")=(lamdaD)/(d)` By equation `y_(5^(@)" min")-y_(1^(@)" max")=7xx10^(-3)` `(9lamdaD)/(2d)-(lamdaD)/(2d)=7xx10^(-3)implieslamda=(7xx10^(-3)xx15xx10^(-5)xx2)/(7xx50xx10^(-2))` `thereforelamda=600nm`

Discussion

No Comment Found

Related InterviewSolutions

Angular width of central maxima in the Fraunhofer diffraction pattern of a slit is measured. The slit is illuminated by light of wavelength `6000Å`. When the slit is illuminated by light of another wavelength, the angular width decreases by 30%. The wavelength of this light will beA. `3500 Å`B. `4200 Å`C. `4700 Å`D. `6000 Å`
Find the half angular width of the central bright maximum in the fraunhofer diffraction pattern of a slit of width `12xx10^(-5)cm` when the slit is illuminated by monochromatic light of wavelength 6000 Å.
Find the half angular width of the central bright maximum in the fraunhofer diffraction pattern of a slit of width `12xx10^(-5)cm` when the slit is illuminated by monochromatic light of wavelength 6000 Å.A. `40^(@)`B. `45^(@)`C. `30^(@)`D. `60^(@)`
In a single slit diffraction, the width of slits is `0.5cm`, focal length of lens is 40 cm and of first dark fringe is
What will be the angular width of central maxima in Fraunhofer diffraction when light of wavelength `6000Å` is used and slit width is `12xx10^-5cm`?A. (a) `2rad`B. (b) `3rad`C. (c) `1rad`D. (d) `8rad`
A light wave is incident normally over a slit of width `24xx10^-5cm`. The angular position of second dark fringe from the central maxima is `30^@`. What is the wavelength of light?A. `6000 Å`B. `5000 Å`C. `3000 Å`D. `1500 Å`
Light of wavelength `6328 Å` is incident normally on a slit of width 0.2 mm. Angular width of the central maximum on the screen will be :A. `0.9^(@)`B. `0.18^(@)`C. `0.54^(@)`D. `0.36^(@)`
Light of wavelength `6328 Å` is incident normally on a slit of width 0.2 mm. Angular width of the central maximum on the screen will be :A. `0.36^(@)`B. `0.18^(@)`C. `0.72^(@)`D. `0.09^(@)`
Light wavelength 6000 Å is incident normally on a slit of width `24xx10^(-5)` cm. find out the angular position of seconds minimum from central maximum?A. `12 xx 10^(-5)cm`B. `18xx10^(-5)cm`C. `24xx10^(-5)cm`D. `36xx10^(-5)cm`
Light wavelength 6000 Å is incident normally on a slit of width `24xx10^(-5)` cm. find out the angular position of seconds minimum from central maximum?

If the distance between the first maxima and fifth minima of a double-slit pattern is 7 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength of the light used isA. 600 nmB. 525 nmC. 467 nmD. 420 nm

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment