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If the distance between the foci of a hyperbola is`16`and its eccentricity is `sqrt(2)`, then obtain its equation. |
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Answer» Distance between the foci of the hyperbola, `2ae =16` Eccentricity of the hyerbola, `e = sqrt2` `:. (2ae)/e = 16/sqrt2` `a = 8/sqrt2 = 4sqrt2` Now, `e^2 = 1+ b^2/a^2` `=>sqrt2^2 = 1 + b^2/(4sqrt2)^2` `=>2 = 1+b^2/32` `=>b^2 = 32(2-1)` `=>b^2 = 32` Equation of a hyperbola is given by, `x^2/a^2-y^2/b^2 = 1` `:.` Equation of the given hyperbola, `=>x^2/32-y^2/32 = 1` `=>x^2-y^2 = 32.` |
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