1.

If the distance between the foci of a hyperbola is`16`and its eccentricity is `sqrt(2)`, then obtain its equation.

Answer» Distance between the foci of the hyperbola,
`2ae =16`
Eccentricity of the hyerbola, `e = sqrt2`
`:. (2ae)/e = 16/sqrt2`
`a = 8/sqrt2 = 4sqrt2`
Now,
`e^2 = 1+ b^2/a^2`
`=>sqrt2^2 = 1 + b^2/(4sqrt2)^2`
`=>2 = 1+b^2/32`
`=>b^2 = 32(2-1)`
`=>b^2 = 32`
Equation of a hyperbola is given by,
`x^2/a^2-y^2/b^2 = 1`
`:.` Equation of the given hyperbola,
`=>x^2/32-y^2/32 = 1`
`=>x^2-y^2 = 32.`


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