If the distance between the plane ax−4y+2z=k and the plane containin – InterviewSolution

1.	If the distance between the plane ax−4y+2z=k and the plane containing the lines x−23=y−34=z−45 and x−34=y−45=z−56 is, 2√6 then \|k\|3 is equal to
Answer» If the distance between the plane $a x - 4 y + 2 z = k$ and the plane containing the lines $\frac{x - 2}{3} = \frac{y - 3}{4} = \frac{z - 4}{5} and \frac{x - 3}{4} = \frac{y - 4}{5} = \frac{z - 5}{6} is, 2 \sqrt{6} then \frac{\| k \|}{3}$ is equal to

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