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If the distance between the point (4,k) and (1,0) is 5, then what can be the possible value of k |
| Answer» Let the points X (4,k) and Y(1,0)It is given that the distance XY is 5 units.By using the distance formula,XY = √ (4-1)2 + (k -0)25 = √9 + k225 = 9 + K2 (squaring on both side)K2 = 16k = ±4 | |