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If the distance of the point P(1,–2,1) from the plane x+2y–2z=α, where α>0, is 5, then the foot of the perpendicular from P to the plane is |
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Answer» If the distance of the point P(1,–2,1) from the plane x+2y–2z=α, where α>0, is 5, then the foot of the perpendicular from P to the plane is |
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