If the distance of the point P(1,−2,1) from the plane x+2y−2z=α, – InterviewSolution

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1.	If the distance of the point P(1,−2,1) from the plane x+2y−2z=α, where α>0, is 5, then the foot of the perpendicular from P to the plane is
Answer» If the distance of the point $P (1, - 2, 1)$ from the plane $x + 2 y - 2 z = α$ , where $α > 0$ , is $5$ , then the foot of the perpendicular from $P$ to the plane is

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