1.

If the E_("cell")^(@) for a given reaction has a negative value, which of the following gives the correct relationships for the values of Delta G^(@) and K_(eq) ?

Answer»

`DELTA G^(@) lt 0, K_(EQ) gt 1`
`Delta G^(@) lt 0, K_(eq) lt 1`
`Delta G^(@) gt 0, K_(eq) lt 1`
`Delta G^(@) gt 0, K_(eq) gt 1`

Solution :`E_("cell")^(@) = -ve`
`Delta G^(@) = -nF " "E_("cell")^(@)`
`Delta G^(@) =+ve rArr Delta G gt 0`
`Delta G^(@) = -2.303 " RT LOG "K_(eq)`
`therefore K_(eq) lt 1`


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