If the earth has a mass nine times and radius twice that of the planet Mars. Given escape speed on the surface of Earth is 11.2 km s^(-1).

If the earth has a mass nine times and radius twice that of the planet

1.	If the earth has a mass nine times and radius twice that of the planet Mars. Given escape speed on the surface of Earth is 11.2 km s^(-1).
Answer» Solution :`g_(m) = g_(e) ((M_(s))/(M_(e))) ((R_(e))/(R_(m)))^(2) = g_(e) xx (1)/(4) xx 4 = (4)/(9) g_(e)` On EARTH, `upsilon_(e) = SQRT(2G_(e) R_(e))`, On Mars, `upsilon_(m) = sqrt(2g_(m) R_(m))` `:. (upsilon_(m))/(upsilon_(e)) = upsilon_(e) xx (sqrt(2))/(3) = (11.2 xx 1.414)/(3)` `= 5.28 km s^(-1)`