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If the eccentricities of the hyperbolas x2a2−y2b2=1 and y2b2−x2a2=1 be e and e1, then 1e2+1e21= |
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Answer» If the eccentricities of the hyperbolas x2a2−y2b2=1 and y2b2−x2a2=1 be e and e1, then 1e2+1e21= |
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