1.

if the edge length of a NaH unit cell is 488 pm, what is the length of Na-H bond if it crystallises in the fcc structure ?A. 122 pmB. 244 pmC. 488 pmD. 976 pm

Answer» Correct Answer - d
NaH has fcc structure similar to that of NaCl. ltbr. Thus, edge length of NaH =` 2( r_(Na^(+)) + r_(H^(-)))`
i.e, ` 2( r_(Na^(+) + r_(H^(-)) = 488 "pm" `
i.e, ` 2( r_(Na^(+)) + r_(H^(-))) = 488 "pm"`
` r_(Na^(+)) + r_(H^(-)) = 244 "pm"` , which is Na -H bond length.


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