If the electron in hydrogen atom jumps from the third orbit to second orbit, the wavelength of the emitted radiation is given by lambda = (36)/(xR) . Then value of x is

If the electron in hydrogen atom jumps from the third orbit to second

1.	If the electron in hydrogen atom jumps from the third orbit to second orbit, the wavelength of the emitted radiation is given by lambda = (36)/(xR) . Then value of x is
Answer» SOLUTION :`1/(lambda) = R[1/(n_1^2) - 1/n_2^2 ] = R [1/2^2 - 1/(3^2)]` `1/(lambda) = (5R)/(36) THEREFORE lambda = (36)/(5R)`