If the electronic configuration of an element is 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 3d^(2) 4s^(2), the four electrons involved in chemical bond formation will be

If the electronic configuration of an element is 1s^(2) 2s^(2) 2p^(6)

1.	If the electronic configuration of an element is 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 3d^(2) 4s^(2), the four electrons involved in chemical bond formation will be
Answer» `3p^(6)` `3p^(6) , 4s^(2)` `3p^(6), 3D^(2)` `3d^(2) , 4s^(2)` Solution :`3d^(2), 4s^(2)` The given electronic configuration indicate that an element is vanadium (Z = 22). It BELONGS to d-block of the periodic table. In transition elements i.e., d-block elements, electrons of ns and (n - l)d subshell take part in BOND formation.