1.

If the ellipse (x^2)/4 + (y^2)/1 = 1 meets the ellipse (x^2)/1 + (y^2)/(a^2)= 1 in four distinct points and a = b^(2) - 10 b + 25, then the number of integral values of b are

Answer»

3
4
6
Infinite

Solution :It is clear that a should be greater than one,
hence `b^(2) - 10B + 25 > 1`
`(b - 4)(b - 6) > 0`
`b > 6 UU b < 4`.


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