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If the EMF of a cell is 1.5 V, then the energy provided by the cell to drive 0.5 C of charge around the circuit : (A) 1 J (B) 0.75 J (C) 0.5 J (D) 0.25 J |
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Answer» (B) 0.75 J Energy = work done (w) = vq w = 1.5 x 0.5 = 0.75J |
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