Saved Bookmarks
| 1. |
If the end correction of an open pipe is 0.8 cm, then the inner radius of that pipe will beA. `1/3`cmB. `2/3` cmC. `3/2` cmD. 0.2cm |
|
Answer» Correct Answer - C For an open organ pipe, the relation between end correction and inner radius of the organ pipe is given by `Deltal=1.2xxr` [`Deltal` end correction, r= inner radius] So, `r=(Deltal)/1.2=(0.8)/1.2` `[because Deltal = 0.8]` `2/3cm` |
|