If the energy difference between two electronic states is 47.5 kcalmol−1 and the frequency of the light emitted when the electrons drop from a higher state to lower states is x×1014, what is the value of x?(N.h=9.5×10−14 kcal s−1mol−1,where, N is the Avogadro's number and h is the Planck's constant)

If the energy difference between two electronic states is 47.5 kcalmol

1.	If the energy difference between two electronic states is 47.5 kcalmol−1 and the frequency of the light emitted when the electrons drop from a higher state to lower states is x×1014, what is the value of x?(N.h=9.5×10−14 kcal s−1mol−1,where, N is the Avogadro's number and h is the Planck's constant)
Answer» If the energy difference between two electronic states is $47.5 k c a l m o l^{- 1}$ and the frequency of the light emitted when the electrons drop from a higher state to lower states is $x \times 10^{14}$ , what is the value of $x$ ? $(N . h = 9.5 \times 10^{- 14} k c a l s^{- 1} m o l^{- 1}, where, N is the Avogadro's number and h is the Planck's constant)$