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If the energy input to a carnot engine is thrice the work it performs then, the fraction of energy rejected to the sink is |
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Answer» `(1)/(3)` Dividing by `Q_(1)` on both SIDES, we get `(W)/(Q_(1)) = 1 - (Q_(2))/(Q_(1))` or `(Q_(2))/(Q_(1)) = 1 - (W)/(Q_(1))` As `Q_(1) = 3W` (given) `:. (Q_(2))/(Q_(1)) = 1 - (W)/(3W) = 1 - (1)/(3) = (2)/(3)` Thus the fraction of energy rejected to the sink is `(2)/(3)`. |
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