If the enthalpy change for the transition of liquid water to steam is 30 kJ/mol""^(-1) at 27°C, the entropy change for the process would be :

If the enthalpy change for the transition of liquid water to steam is

1.	If the enthalpy change for the transition of liquid water to steam is 30 kJ/mol""^(-1) at 27°C, the entropy change for the process would be :
Answer» 10 J mol`""^(-1) K^(-1)` 1.0 J mol`""^(-1) K^(-1)` 0.1 J mol`""^(-1) K^(-1)` 100 J mol`""^(-1) K^(-1)` Solution :Given `DELTA H = 30` KJ mol`""^(-1) T = 273+ 27 = 300` K `Delta S_(T) = (Delta H_(T) )/( 300) "J mol"^(-1)` `= 100"J mol"^(-1) K^(-1)`