If the equation for the displacement of a particle moving in a circular path is given by `(theta)=2t^(3)+0.5`, where `theta` is in radians and `t` in seconds, then the angular velocity of particle after `2 s` from its start isA. `8 rad//s`B. `12 rad//s`C. `24 rad//s`D. `36 rad//s`

If the equation for the displacement of a particle moving in a circula

1.	If the equation for the displacement of a particle moving in a circular path is given by `(theta)=2t^(3)+0.5`, where `theta` is in radians and `t` in seconds, then the angular velocity of particle after `2 s` from its start isA. `8 rad//s`B. `12 rad//s`C. `24 rad//s`D. `36 rad//s`
Answer» `theta=2t^(3)+0.5` `omega=(d theta)/(dt)=6t^(2)` At `t=2 s, omega=6(2)^(2)=24 rad//s`

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If the equation for the displacement of a particle moving in a circular path is given by `(theta)=2t^(3)+0.5`, where `theta` is in radians and `t` in seconds, then the angular velocity of particle after `2 s` from its start isA. `8 rad//s`B. `12 rad//s`C. `24 rad//s`D. `36 rad//s`

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