1.

If the equation has no real root, then lamda lies in the interval

Answer»

`(-oo,0)`
`(-oo,6)`
`(6,oo)`
`(0,oo)`

Solution :If equation has no REAL roots, then (1) must have both roots negative for which
`(-b)/(2a)lt0implieslamdalt0""(5)`
`f(0)gt0or9gt0`
`:.lamdain(-oo,6)""["form"(2),(3),(5)]`
ALSO for no real roots we can have `Dlt0`
`implieslamda^(2)-36lt0implieslamdain(-6,6)`
HENCE, `lamdain(-oo,6)`


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