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If the equation of alternating emf is V = 200 sin 300t, then for a circuit containing R = 100 `Omega` and L = 800 mH, the peak value of current will be in ampere :A. 0.77B. `2.0`C. 1.5D. 1.83 |
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Answer» Correct Answer - A `X_L=(300xx800)/1000`=240 R=100 `i=V/Z =200/sqrt(100^2 + 240^2)` |
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