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If the equation of family of ellipse is x^(2)sec^(2)theta+y^(2)cosec^(2)theta=1, where pi/4ltthetaltpi/2, then the locus of extremities of the latusrectum is |
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Answer» `2y^(2)(1+x^(2))=(1-x^(2))^(2)` |
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