1.

If the equation of family of ellipse is x^(2)sec^(2)theta+y^(2)cosec^(2)theta=1, where pi/4ltthetaltpi/2, then the locus of extremities of the latusrectum is

Answer»

`2y^(2)(1+x^(2))=(1-x^(2))^(2)`
`2x^(2)(1+y^(2)=(1-y^(2))^(2)`
`2y(1-x^(2))=1+x^(2)`
`2y^(2)(1+x^(2))=1+x^(4)-2x^(2)`

ANSWER :B::D


Discussion

No Comment Found

Related InterviewSolutions