InterviewSolution
Saved Bookmarks
| 1. |
If the equation of the parabola whose focus is the point of intersection of x+y=3, x−y=1 and directrix is x−y+5=0, is ax2+bxy+cy2+dx+ey−15=0, then the radius of the circle ax2+cy2+dx+ey−10=0 is equal to |
|
Answer» If the equation of the parabola whose focus is the point of intersection of x+y=3, x−y=1 and directrix is x−y+5=0, is ax2+bxy+cy2+dx+ey−15=0, then the radius of the circle ax2+cy2+dx+ey−10=0 is equal to |
|