1.

If the equation of the parabola whose focus is the point of intersection of x+y=3, x−y=1 and directrix is x−y+5=0, is ax2+bxy+cy2+dx+ey−15=0, then the radius of the circle ax2+cy2+dx+ey−10=0 is equal to

Answer»

If the equation of the parabola whose focus is the point of intersection of x+y=3, xy=1 and directrix is xy+5=0, is ax2+bxy+cy2+dx+ey15=0, then the radius of the circle ax2+cy2+dx+ey10=0 is equal to



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