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If the equation x2 – bx + 1 = 0 does not possess real roots, thenA. – 3 < b < 3 B. – 2 < b < 2 C. b > 2 D. b < – 2 |
Answer» If the equation does not possess real roots then d = b2 – 4ac = 0 Here a = 1, b = – b, c = 1 d = b2 – 4 < 0 b2 < 4 b < \(\pm\) 2 – 2 < b < 2 |
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