1.

If the equation x2 – bx + 1 = 0 does not possess real roots, thenA. – 3 < b < 3 B. – 2 < b < 2 C. b > 2 D. b < – 2

Answer»

If the equation does not possess real roots then 

d = b2 – 4ac = 0 

Here a = 1, b = – b, c = 1 

d = b2 – 4 < 0 

b2 < 4 

b < \(\pm\)

– 2 < b < 2



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