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If the equatoin ax^(2)-y^(2)+bx+cy+d=0 represents a pair of lines whose slopes are m and m^(2), then value (s) of a is /are |
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Answer» `a=-8` `((y)/(X))^(2)-6((y)/(x))+a=0` `:. m+m^(2)=6andm^(3)=a` or`m^(3)+m^(6)+3m^(3)(m+m)=216` `a+a^(2)+3A*6=216` `a^(2)+19a-216=0or a=8,a=-27` |
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